Titanium Edge

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Crazy About Callaway Diablo Edge Series?

Crazy About Callaway Diablo Edge Series?z

Callaway Diablo Edge Driver

The Diablo Edge Drivers are designed to give golfers a distance advantage every time you tee it up, which offer superior face technology, a higher MOI, a deeper CG, and better aerodynamics — and it all adds up to the longest, most accurate all-titanium drivers Callaway Golf has ever made. The 4-piece Fused Titanium design creates the most weight efficient titanium driver Callaway has ever made, generating long, penetrating trajectories. The chemically milled Hyperbolic Face produces Callaway's highest, most consistent ball speeds over the entire face. The new aerodynamic body shape reduces drag during the downswing up to 8%, creating faster impact speeds.

Callaway Diablo Edge Fairway Wood

The new Diablo Edge Fairway Woods are the longest, straightest steel fairway woods we've ever made, with distance gains of 10-12 yards over Big Bertha Diablo. That's not just better, that's a game changer. The Diablo Edge Tour Fairways possess the lowest, shallowest CG of any steel fairway wood we've ever made, providing skilled players with a cheap golf clubthat will perform more to their liking.

Greater Forgiveness

With more weight positioned in the extreme perimeter of the clubhead, Diablo Edge Fairway Woods have the highest moment of inertia (MOI) ever in a steel Callaway fairway wood. That means less clubhead twisting at impact and, therefore, greater forgiveness.

VFT Face Pattern

Delivering higher ball speeds for increased distance, the new, more aggressive VFT face pattern makes these fairway woods dramatically hotter.

High, Distance-Enhancing Trajectories

The standard Diablo Edge Fairway Woodsfeature the deepest center of gravity (CG) of any fairway wood Callaway has ever made for high, distance-enhancing trajectory. The Diablo Edge Tour Fairway Woods have the lowest, shallowest CG of any steel Callaway fairway woods ever made for a flat, penetrating ball flight that is preferred by better players.

Callaway Diablo Edge Irons

The longest stainless steel irons Callaway has ever created so far.  Debuting on Jan. 15, 2010, the Diablo Edge irons provide increased distances compromising neither feel nor performance. Its lower, deeper center of gravity (CG) makes the sweet spot more accessible and is in line with where the ball most commonly hit by amateurs on the clubface, generating longer, consistent distance and improving accuracy.

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Titanium metal has a body-centered cubic unit cell. The density of titanism is 4.50 g/cm^3.?

Calculate the edge length of the unit cell and a value for the atomic radius of titanium. (Hint: In a body-centered arrangement of spheres, the spheres tough across the body diagonal.

I know how to get the length factor label and then cubing when I get the answer in cm from the density. How do I then find the radius? Can I use the pythagorean theorem as in the face-cenetered cubic cell? If not, what equation should I use instead. I was told to do it this way but I don't understand. Please explain.

length=328 pm.

Take the square root of 328^2 + 328^2 = x.
x= 464
328^2 + 464 ^2= 4r^2
32280 = 16r^2
Divide by 16.
r= 45 pm

Is this right?

(volume / g) x (g / mole) x (mole / atoms) x (atoms / cell) = (volume / cell)

do you see that? everything cancels except volume and cell. and since this is a cube, the cube root of the volume = the edge length.

volume / g = 1 cm^3 / 4.50g
g / mole = the molar mass of titanium from a periodic table
moles / atoms = 1 mole / 6.022x10^23 atoms
atoms / cell = 2

fyi.. atoms / cell = 2 because there are 8 corner atoms. each of those exists in 8 adjacent cells. so only 1/8th of each corner atom is in any given cell.. 8 x 1/8 = 1.. and 1 center atom makes 2 per cell.

see this picture

http://www.google.com/imgres?imgurl=http://mrsec.wisc.edu/Edetc/SlideShow/images/unit_cells/body_centered_cubic2.jpg&imgrefurl=http://www.mrsec.wisc.edu/Edetc/SlideShow/slides/unit_cells/body_centered_cubic.html&h=336&w=320&sz=32&tbnid=d4zt8lnJ5tYkYM:&tbnh=119&tbnw=113&prev=/images%3Fq%3Dbody%2Bcentered%2Bcubic%2Bunit%2Bcell&hl=en&usg=__qmlkHDPuNfByyCqvwlzI4te3GzU=&ei=9o9DS7GMMJKENv_fnYIJ&sa=X&oi=image_result&resnum=4&ct=image&ved=0CA8Q9QEwAw

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As to the radius....

this is complicated. look at this picture

http://www.chem.lsu.edu/htdocs/people/sfwatkins/merlot/lattice/03bcc.html

the diagonal of the cube = line from the upper left front corner through the center atom to the lower right back atom. ok? those atoms touch. and since the corner atoms are only partially in a unit cell.. from the center of the atom on, the length of that diagonal = 1 radius from the upper left atom + 2 radius from the center atom + 1 radius for the lower right atom. got it?

and that diagonal forms a right triangle with 1 leg being the edge from the upper left front atom to the lower left front atom and the other leg being the diagonal of the bottom FACE of the cube. and that diagonal has 2 legs both being edge lengths. lower left front to lower right front and lower right front to lower right back.. got that?

thanks to pythagoreus...
(FACE diagonal length)² = (edge length)² + (edge length)²

(CUBE diagonal length)² = (edge length)² + (FACE diagonal length)²

(CUBE diagonal length)² = (edge length)² + ((edge length)² + (edge length)²

(CUBE diagonal length)² = 3 x (edge length)²

CUBE diagonal length = √3 x edge length..

4r = √3 x edge length..

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can you finish?

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